p^2+5/2=27

Solution for p^2+5/2=27 equation:

p^2+5/2=27

We move all terms to the left:

p^2+5/2-(27)=0

determiningTheFunctionDomain
p^2-27+5/2=0

We multiply all the terms by the denominator


p^2*2+5-27*2=0

We add all the numbers together, and all the variables

p^2*2-49=0

Wy multiply elements

2p^2-49=0

a = 2; b = 0; c = -49;
Δ = b2-4ac
Δ = 02-4·2·(-49)
Δ = 392
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{392}=\sqrt{196*2}=\sqrt{196}*\sqrt{2}=14\sqrt{2}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{2}}{2*2}=\frac{0-14\sqrt{2}}{4}
=-\frac{14\sqrt{2}}{4}
=-\frac{7\sqrt{2}}{2}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{2}}{2*2}=\frac{0+14\sqrt{2}}{4}
=\frac{14\sqrt{2}}{4}
=\frac{7\sqrt{2}}{2}
$